25x^2+95x+88=0

Solution for 25x^2+95x+88=0 equation:

25x^2+95x+88=0

a = 25; b = 95; c = +88;
Δ = b2-4ac
Δ = 952-4·25·88
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-15}{2*25}=\frac{-110}{50}
=-2+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+15}{2*25}=\frac{-80}{50}
=-1+3/5
$